Laplace transforms

A time-domain signal $$f(t)$$ is represented by the following expression in the frequency domain:

$$F(s)=1/(s^2+9s$$

The final value of $$f(t)$$ is most nearly:

The circuit shown below has a transfer function given by:

$$V_("out")/V_("in")=(1.2(s+2))/((s+1)(s+4))$$

The voltage source $$v_("in")(t)$$ is a unit step function, and there is no initial charge on the capacitors.  The final (steady-state) value (V) of  $$v_("out")(t)$$ is most nearly:

A.   0
B.   0.04
C.   0.55
D.   0.60