Given the programming diagram below for a PLD, what is the logic implemented at Output X?

A.  $$AB+barAbarB$$
B.  $$AbarB+barAB$$
C.  $$AbarB$$
D.  $$barAB$$

1 Answer

James Dowd

Updated on December 26th, 2020

In the following diagram, we have the following three gates:

INVERTER with output: A¯

AND gate with output: A·B

OR gate with output: A+B

Walking through the PLD for output X, we can write the logic as follows:

X = (A¯·B) + (A·B¯) X = A¯B+ AB¯

This corresponds to answer B.

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