A sea vessel accelerates at a rate of $$22\ ft//sec^2$$. The vessel travels 140 ft while its speed changes to 70 ft/sec. The initial velocity (ft/sec) was most nearly:
A sea vessel accelerates at a rate of $$22\ ft//sec^2$$. The vessel travels 140 ft while its speed changes to 70 ft/sec. The initial velocity (ft/sec) was most nearly:
1 Answer
Ethan A Croyle
Updated on December 26th, 2020v_f^2=V_0^2-2xaxd
v_f=70ft/sec
d=140ft
a=22ft/sec^2
V0=sqrt(v_f^2+2xaxd)=sqrt(70^2+2x22x140)=105.17ft/sec in the negative direction
(directions not given but necessary for problem solution)
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