A Newtonian fluid flows through 2-in. commercial steel pipe (I.D. = 0.0525 m). 

Liquid Properties: 
Density = 1.00 g/mL
Viscosity = 1.05 cP 
Flow= 0.500 $$m^3//min$$

The Reynolds number is most nearly: 

A.   $1.93\times {10}^3$
B.   $7.94\times {10}^3$
C.   $1.93\times {10}^5$
D.   $1.15\times {10}^7$

ID incorrect should be .0508 m for a 2 in. pipe, but continuing with given numbers…

Re=(rho*u*D)/(Mu)

rho=1 g/mL= 1000 kg/m^3

D=.0525 m

A=area=(pi*D^2)/4 m^2

volume/min=(.5* m^3/min)

u=volume/min x(1min/60sec)x(1/A)=.5(m^3/min)x (1min/60sec)x(1/((pi*.0525^2)/4))=~3.85

Mu=viscosity=1.05cP=1.05*10^-3 Pa*s (assuming dynamic viscosity)

Re=(1000x3.85x.0525)/(1.05x10^-3)=192477.6 nearly reaching to C 522 difference